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Apply this algorithm to Table 4-1, which shows an example of tasks and dependencies. The same dependencies are shown in Fig. 4-3. To apply the completion time algorithm, start with subtask a; it has no dependencies, so it can start at the initial time (say, 0). It can complete at time 0 8 8. Similarly, subtask b can complete at time 0 10 10. See Table 4-2. Note that since these subtasks are not dependent on each other or on anything else, they can start at time 0. Their completion times are calculated without concern for lack of resources. That is, for this completion calculation, it assumes that there are people available to do both tasks at the same time. Table 4-1 Subtask ID a b c d e f g h i Subtasks Dependencies

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main0 int a, b, c; tout < < "Enter three tin >> a >> b >> c; i f (a >= b && a >= c) if (b >= a ai b >= c) i f (c >= a && c >= b)

integers:

tout << a CC endl; tout << b << endl; tout C-C c << endl; .. . .

This simply checks each of the three numbers to see which is greater than or equal to the other two.

Fig. 4-3.

Note that Example 2.10 is no improvement over Example 2.8. Its purpose was simply to illustrate the use of compound conditionals. Here is another example using a compound conditional:

or a y for yes :

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main0 -t char ans; tout << "Are you enrolled (y/n): "; tin >> ans; if (ans == 'Y' I I ans == 'y') tout << "You are enrolled.\n"; else tout << "You are not enrolled.\n"; >

It prompts the user for an answer, suggesting a response of either Y or n. But then it accepts any character and concludes that the user meant no unless either a Y or a Y is input. Compound conditionals that use scsc and I I will not even evaluate the second part of the conditional unless necessary. This is called short-circuiting. As the truth tables show, (p GCSC q> will be false if p is false. So in that case there is no need to evaluate g if p is false. Similarly if p is true then there is no need to evaluate g to determine that (p I I q> is true. The value of short circuiting can be seen from the following example:

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Since the completion times for subtasks a and b are now calculated, the completion times for nodes c, d, and e can be calculated. Since the predecessors of c finish at 8 and 10, subtask c can start at 10 and complete at 10 + 8 = 16. The start time for d will be 8 and the completion time can be 8 + 9 = 17, and for e the times will be 10 and 10 + 5 = 14. Now we can process subtasks f and g. The start times can be 17 and 16, respectively. The completion times will be 17 + 3 = 20 for f and 16 + 2 = 18 for g. Subtasks h and i can now be calculated with both starting at 21 and h competing at 25 and i at 24. Table 4-2 has all of the start and completion times.

6.1 d. all of the above. The context consists of a context node, a context position and size, variable bindings, and an initial context. 6.2 a, d, and e. The and \ are not part of the XPath syntax. 6.3 d. The / is the symbol for root. 6.4 b. Axes refer to the relationship between the nodes of a document. 6.5 The axes are child, descendant, parent, ancestor, sibling, following sibling, preceding sibling, following, preceding, self, descendent or self, and ancestor or self. 6.6 a and b. Variable reference and function call 6.7 Number, node set, Boolean, string 6.8 a, c, and d. int(), round(), and true() are Boolean, and concat() is a string function. 6.9 No, the data model for 1.0 is more conceptual in nature, and 2.0 is more implementable. 6.10 Yes, it is most important as of version XPath 2.0.

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